debug-mode: report error when query is not simulatable #243
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staabm
commented
Feb 4, 2022
| @@ -119,6 +119,10 @@ public function getResultType(string $queryString, int $fetchType): ?Type | |||
| { | |||
| $result = $this->simulateQuery($queryString); | |||
| if (!\is_array($result)) { | |||
| if (QueryReflection::getRuntimeConfiguration()->isDebugEnabled() && $result instanceof mysqli_sql_exception) { | |||
| throw new UnresolvableQueryException(sprintf("Cannot simulate query\n %s \nbecause of a sql error: %s", $queryString, $result->getMessage())); | |||
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todo: separate exception type
staabm
changed the title
|
Todo: make this report a phpstan error instead of a uncaught exception |
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to ease debugging of errors like #225 (comment)